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3y^2-15y-18=0
a = 3; b = -15; c = -18;
Δ = b2-4ac
Δ = -152-4·3·(-18)
Δ = 441
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{441}=21$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-15)-21}{2*3}=\frac{-6}{6} =-1 $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-15)+21}{2*3}=\frac{36}{6} =6 $
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